To determine the number of ways to achieve a sum of 6 when rolling a standard 6-faced die three times, we can approach the problem as follows: We start by creating a matrix called 'ways' with dimensions (x+1)*(n+1), where x is the target sum and n represents the number of rolls. It is important to note that it is impossible to achieve any sum (other than 0) with zero rolls, so we assign ways[i][0] = 0 for all i > 0. Conversely, for a sum of 0, regardless of the number of rolls, there is exactly one way to achieve this (i.e., by not rolling the die). Our objective is to find the value of ways[x][n], using combinations derived from earlier calculations. To do this, we iterate through each possible sum from 1 to x for every number of rolls from 1 to n. For each combination, we compute ways[i][j] by adding up ways[i-k][j-1] for every k from 1 to the number of die faces, stopping when i-k = 0. Returning to our specific case where the target sum is 6, the number of rolls is 3, and the die has 6 faces, we find through this process that there are 10 distinct ways to achieve a sum of 6 with three rolls of the die.