I will utilize a hash map to keep track of the pairs, enabling quick look-ups and effectively managing this task. Consider we have an array of pairs like [(1,2), (2,1), (3,4), (5,6), (6,5), (7,8)]. Here’s a Python implementation: def find_symmetric_pairs(arr): # Initialize an empty hash map to store pairs pair_dict = {} # Loop through the entire array for i in range(len(arr)): first = arr[i][0] second = arr[i][1] # Check if the second element of this pair exists in pair_dict # and if its value corresponds to the first element of this pair, # indicating a symmetric pair if (second in pair_dict and pair_dict[second] == first): print("(" + str(second) + ", " + str(first) + ")") else: pair_dict[first] = second find_symmetric_pairs([(1,2), (2,1), (3,4), (5,6), (6,5), (7,8)]) In the code provided, we traverse the array just once. For each pair, we check if its reverse is already present in our hash map; if it is, we print it out; otherwise, we add it to our hash map.