Removing a node from a Binary Search Tree (BST) necessitates preserving the condition that all nodes in the left subtree of any given node are less than or equal to that node's value, while all nodes in the right subtree are greater than that value. To perform the deletion, we must first locate the target node. If the node is a leaf (has no children), we can easily eliminate it from the tree. If it has one child, we can remove the node and substitute it with its subtree. However, if the node has two children, we must identify a replacement node that maintains the binary search tree property when swapping it with the node to be deleted. Suitable candidates for this are the in-order successor or predecessor. Regarding complexity, the worst-case time complexity for deleting a node from a BST is O(h), where h represents the height of the tree, as this operation requires traversing from the root to a leaf node.