For instance, if the array provided is [10, 20, 30, 40], the result should be 2. Even though the elements in the array are arranged in increasing order, the longest alternating subsequence is only of length 2. To begin, set up two counters, both initialized to 1, representing the lengths of the longest increasing and decreasing subsequences observed so far. Iterate through the array, comparing each element to the one before it. In this case, since all the numbers are increasing, they do not create an alternating subsequence. Consequently, the longest decreasing subsequence remains at 1, while the longest increasing subsequence grows to 4 by the end of the iteration. The maximum of these counters is 4. However, this count includes all four elements; typically, we should count only those that are strictly increasing or strictly decreasing. Therefore, the longest alternating subsequence is of length 2, which can consist of any two numbers from the sequence.