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If you have a vector containing many values, the majority of which are zeros, how would you create a data structure to represent it?

Approach / Explanation

This question assesses your understanding of data structure design and how to optimize data representation, particularly focusing on sparse vector representation. Sparse vectors are generally large, with the majority of their elements being zeros. If stored using traditional methods, they would consume a significant amount of memory. Thus, the question asks you to suggest a more efficient approach for storing this type of data. You should take into account: The space efficiency of the data structure: how to reduce the memory usage of the data structure, considering that most elements are zero. The time efficiency of the data structure: how to ensure that operations such as retrieval, addition, and deletion can still be executed swiftly, even with the emphasis on space efficiency. Keep in mind: When representing a sparse vector, utilize the indices of the non-zero elements along with their respective values.

Suggested Answer

If I needed to work with a large vector predominantly filled with zero values, I would utilize a HashMap . A HashMap offers an effective method for storing and retrieving key-value pairs, making it ideal for representing a sparse vector. Here, the keys would correspond to the indices of the non-zero elements, while the values would be the non-zero elements themselves. This approach is space-efficient since it only stores data for the non-zero elements. Additionally, HashMap ensures time efficiency by providing constant-time performance for basic operations (get and put), as long as the hash function distributes the elements effectively across the buckets.

Alternative Answer

Another effective data structure for this task is an Array of Pairs (or 2D array ), where the first components of the pairs represent the indices of the non-zero elements, and the second components are the respective non-zero values. Although it may be somewhat less efficient than a HashMap regarding search operations (as it may require iterating through all elements), this method is comparably efficient in terms of space complexity since it only stores the non-zero elements along with their indices. This technique could be beneficial when we need to preserve the order of the non-zero elements. Furthermore, if the quantity of non-zero elements is relatively small or if the addition of new elements occurs infrequently, this method might prove to be more efficient than utilizing a HashMap.

Question Details

Difficulty & Category

Medium
data structures

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