This seemingly straightforward question can be tricky if not tackled properly. It inquires about the method to 'sort' an array consisting solely of 0's. Remember that sorting an array typically means rearranging its elements in a specific order, such as ascending or descending. However, since this array contains only 0's, the usual sorting concept may not apply as expected. Here are the main points to help you grasp and respond effectively: Recognize that your array contains only one unique element , which is 0. Thus, no matter how you sort it, the resulting array will remain unchanged. Think about edge cases . Consider factors like the array's size or whether it is empty. Addressing these points can demonstrate your thorough understanding.

Since the array consists solely of 0's, it is inherently sorted regardless of its length. There is no need for a sorting algorithm because there is only one distinct element present in the array. You simply need to return the array as it is. In Python, the implementation could be as follows: def sort_zeros ( array ) : return array If you want to account for the edge case of an empty array, it would be treated the same way. An empty array is also considered sorted, so this scenario does not alter the outcome.

Alternatively, you might want to expand on this idea with the understanding that the input may not always be accurate and that the array could contain non-zero integers. In such instances, more advanced sorting algorithms such as quick sort or bubble sort could be applied. Below is an example using a straightforward sorting method in Python: def sort_zeros ( array ) : return sorted ( array , key = lambda x : 1 if x != 0 else 0 ) This function will arrange the array by moving all non-zero elements to the end, effectively sorting an array that ideally should contain only zeros. Keep in mind, this is based on the premise that the input might be flawed, adding complexity to the situation beyond what it may seem at first glance.